-22=2(-2+3n)-3(-2n+2)

Solution for -22=2(-2+3n)-3(-2n+2) equation:

-22=2(-2+3n)-3(-2n+2)

We move all terms to the left:

-22-(2(-2+3n)-3(-2n+2))=0

We add all the numbers together, and all the variables

-(2(3n-2)-3(-2n+2))-22=0


We calculate terms in parentheses: -(2(3n-2)-3(-2n+2)), so:

2(3n-2)-3(-2n+2)

We multiply parentheses

6n+6n-4-6

We add all the numbers together, and all the variables

12n-10

Back to the equation:

-(12n-10)


We get rid of parentheses

-12n+10-22=0

We add all the numbers together, and all the variables

-12n-12=0

We move all terms containing n to the left, all other terms to the right

-12n=12

n=12/-12

n=-1