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10x=1/2x
We move all terms to the left:
10x-(1/2x)=0
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
10x-(+1/2x)=0
We get rid of parentheses
10x-1/2x=0
We multiply all the terms by the denominator
10x*2x-1=0
Wy multiply elements
20x^2-1=0
a = 20; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·20·(-1)
Δ = 80
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{80}=\sqrt{16*5}=\sqrt{16}*\sqrt{5}=4\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{5}}{2*20}=\frac{0-4\sqrt{5}}{40} =-\frac{4\sqrt{5}}{40} =-\frac{\sqrt{5}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{5}}{2*20}=\frac{0+4\sqrt{5}}{40} =\frac{4\sqrt{5}}{40} =\frac{\sqrt{5}}{10} $
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