-22(3x+2)(x-10)=0

Solution for -22(3x+2)(x-10)=0 equation:

-22(3x+2)(x-10)=0

We multiply parentheses ..

-22(+3x^2-30x+2x-20)=0

We multiply parentheses

-66x^2+660x-44x+440=0

We add all the numbers together, and all the variables

-66x^2+616x+440=0

a = -66; b = 616; c = +440;
Δ = b2-4ac
Δ = 6162-4·(-66)·440
Δ = 495616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{495616}=704$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(616)-704}{2*-66}=\frac{-1320}{-132}
=+10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(616)+704}{2*-66}=\frac{88}{-132}
=-2/3
$