1+(6x-8)=(-8x+1)+20

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Solution for 1+(6x-8)=(-8x+1)+20 equation: 



1+(6x-8)=(-8x+1)+20

We move all terms to the left:

1+(6x-8)-((-8x+1)+20)=0

We get rid of parentheses

6x-((-8x+1)+20)-8+1=0



We calculate terms in parentheses: -((-8x+1)+20), so:

(-8x+1)+20

We get rid of parentheses

-8x+1+20

We add all the numbers together, and all the variables

-8x+21

Back to the equation:

-(-8x+21)



We add all the numbers together, and all the variables

6x-(-8x+21)-7=0

We get rid of parentheses

6x+8x-21-7=0

We add all the numbers together, and all the variables

14x-28=0

We move all terms containing x to the left, all other terms to the right

14x=28

x=28/14

x=2

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