-20z+20=-3(10z+20)

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Solution for -20z+20=-3(10z+20) equation: 



-20z+20=-3(10z+20)

We move all terms to the left:

-20z+20-(-3(10z+20))=0



We calculate terms in parentheses: -(-3(10z+20)), so:

-3(10z+20)

We multiply parentheses

-30z-60

Back to the equation:

-(-30z-60)



We get rid of parentheses

-20z+30z+60+20=0

We add all the numbers together, and all the variables

10z+80=0

We move all terms containing z to the left, all other terms to the right

10z=-80

z=-80/10

z=-8

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