-20(x*x)+2x+3=(4x-5)+(-x+1)(20x+1)-2-19x

Solution for -20(x*x)+2x+3=(4x-5)+(-x+1)(20x+1)-2-19x equation:

-20(x*x)+2x+3=(4x-5)+(-x+1)(20x+1)-2-19x

We move all terms to the left:

-20(x*x)+2x+3-((4x-5)+(-x+1)(20x+1)-2-19x)=0

We add all the numbers together, and all the variables

-20(+x*x)+2x-((4x-5)+(-1x+1)(20x+1)-2-19x)+3=0

We add all the numbers together, and all the variables

2x-20(+x*x)-((4x-5)+(-1x+1)(20x+1)-2-19x)+3=0

We multiply parentheses

-20x^2+2x-((4x-5)+(-1x+1)(20x+1)-2-19x)+3=0

We multiply parentheses ..

-20x^2-((4x-5)+(-20x^2-1x+20x+1)-2-19x)+2x+3=0


We calculate terms in parentheses: -((4x-5)+(-20x^2-1x+20x+1)-2-19x), so:

(4x-5)+(-20x^2-1x+20x+1)-2-19x

determiningTheFunctionDomain
(-20x^2-1x+20x+1)+(4x-5)-19x-2

We add all the numbers together, and all the variables

(-20x^2-1x+20x+1)-19x+(4x-5)-2

We get rid of parentheses

-20x^2-1x+20x-19x+4x+1-5-2

We add all the numbers together, and all the variables

-20x^2+4x-6

Back to the equation:

-(-20x^2+4x-6)


We get rid of parentheses

-20x^2+20x^2-4x+2x+6+3=0

We add all the numbers together, and all the variables

-2x+9=0

We move all terms containing x to the left, all other terms to the right

-2x=-9

x=-9/-2

x=4+1/2