g-1=(2g+-6)3+g3

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Solution for g-1=(2g+-6)3+g3 equation: 



g-1=(2g+-6)3+g3

We move all terms to the left:

g-1-((2g+-6)3+g3)=0

We add all the numbers together, and all the variables

g-((2g-6)3+g3)-1=0



We calculate terms in parentheses: -((2g-6)3+g3), so:

(2g-6)3+g3

We add all the numbers together, and all the variables

g^3+(2g-6)3

We multiply parentheses

g^3+6g-18

We do not support egpression: g^3

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