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-2/5w-21=-7/10w
We move all terms to the left:
-2/5w-21-(-7/10w)=0
Domain of the equation: 5w!=0
w!=0/5
w!=0
w∈R
Domain of the equation: 10w)!=0We get rid of parentheses
w!=0/1
w!=0
w∈R
-2/5w+7/10w-21=0
We calculate fractions
(-20w)/50w^2+35w/50w^2-21=0
We multiply all the terms by the denominator
(-20w)+35w-21*50w^2=0
We add all the numbers together, and all the variables
35w+(-20w)-21*50w^2=0
Wy multiply elements
-1050w^2+35w+(-20w)=0
We get rid of parentheses
-1050w^2+35w-20w=0
We add all the numbers together, and all the variables
-1050w^2+15w=0
a = -1050; b = 15; c = 0;
Δ = b2-4ac
Δ = 152-4·(-1050)·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-15}{2*-1050}=\frac{-30}{-2100} =1/70 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+15}{2*-1050}=\frac{0}{-2100} =0 $
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