-2/5(10c-20)-5=-30

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Solution for -2/5(10c-20)-5=-30 equation: 



-2/5(10c-20)-5=-30

We move all terms to the left:

-2/5(10c-20)-5-(-30)=0



Domain of the equation: 5(10c-20)!=0

c∈R



We add all the numbers together, and all the variables

-2/5(10c-20)+25=0

We multiply all the terms by the denominator


25*5(10c-20)-2=0

Wy multiply elements

125c(1-2=0

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