A=180(n-2)n=3

Solution for A=180(n-2)n=3 equation:

=180(A-2)A=3

We move all terms to the left:

-(180(A-2)A)=0


We calculate terms in parentheses: -(180(A-2)A), so:

180(A-2)A

We multiply parentheses

180A^2-360A

Back to the equation:

-(180A^2-360A)


We get rid of parentheses

-180A^2+360A=0

a = -180; b = 360; c = 0;
Δ = b2-4ac
Δ = 3602-4·(-180)·0
Δ = 129600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{129600}=360$
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(360)-360}{2*-180}=\frac{-720}{-360}
=+2
$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(360)+360}{2*-180}=\frac{0}{-360}
=0
$