-2/3(x-9)=1/3x

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Solution for -2/3(x-9)=1/3x equation: 



-2/3(x-9)=1/3x

We move all terms to the left:

-2/3(x-9)-(1/3x)=0



Domain of the equation: 3(x-9)!=0

x∈R





Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-2/3(x-9)-(+1/3x)=0

We get rid of parentheses

-2/3(x-9)-1/3x=0

We calculate fractions


(-6x)/(9x^2-81x)+(-3xx/(9x^2-81x)=0



We calculate terms in parentheses: +(-3xx/(9x^2-81x), so:

-3xx/(9x^2-81x

We multiply all the terms by the denominator


-3xx

Back to the equation:

+(-3xx)



We get rid of parentheses

(-6x)/(9x^2-81x)-3xx=0

We multiply all the terms by the denominator


(-6x)-3xx*(9x^2-81x)=0

We multiply parentheses

-27x^3+243x^2+(-6x)=0

We get rid of parentheses

-27x^3+243x^2-6x=0

We do not support expression: x^3

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