-2/3(9x+12)+2x=-2/5(10x-4)

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Solution for -2/3(9x+12)+2x=-2/5(10x-4) equation: 



-2/3(9x+12)+2x=-2/5(10x-4)

We move all terms to the left:

-2/3(9x+12)+2x-(-2/5(10x-4))=0



Domain of the equation: 3(9x+12)!=0

x∈R





Domain of the equation: 5(10x-4))!=0

x∈R



We add all the numbers together, and all the variables

2x-2/3(9x+12)-(-2/5(10x-4))=0

We calculate fractions


2x+(-10x1/(3(9x+12)*5(10x-4)))+(-(-6x9)/(3(9x+12)*5(10x-4)))=0



We calculate terms in parentheses: +(-10x1/(3(9x+12)*5(10x-4))), so:

-10x1/(3(9x+12)*5(10x-4))

We multiply all the terms by the denominator


-10x1

We add all the numbers together, and all the variables

-10x

Back to the equation:

+(-10x)





We calculate terms in parentheses: +(-(-6x9)/(3(9x+12)*5(10x-4))), so:

-(-6x9)/(3(9x+12)*5(10x-4))

We add all the numbers together, and all the variables

-(-6x^9)/(3(9x+12)*5(10x-4))

We multiply all the terms by the denominator


-(-6x^9)

We do not support expression: x^9

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