-2+y+y-10=4(3y-8)

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Solution for -2+y+y-10=4(3y-8) equation: 



-2+y+y-10=4(3y-8)

We move all terms to the left:

-2+y+y-10-(4(3y-8))=0

We add all the numbers together, and all the variables

2y-(4(3y-8))-12=0



We calculate terms in parentheses: -(4(3y-8)), so:

4(3y-8)

We multiply parentheses

12y-32

Back to the equation:

-(12y-32)



We get rid of parentheses

2y-12y+32-12=0

We add all the numbers together, and all the variables

-10y+20=0

We move all terms containing y to the left, all other terms to the right

-10y=-20

y=-20/-10

y=+2

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