10(y+3)+2y=18

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Solution for 10(y+3)+2y=18 equation: 



10(y+3)+2y=18

We move all terms to the left:

10(y+3)+2y-(18)=0

We add all the numbers together, and all the variables

2y+10(y+3)-18=0

We multiply parentheses

2y+10y+30-18=0

We add all the numbers together, and all the variables

12y+12=0

We move all terms containing y to the left, all other terms to the right

12y=-12

y=-12/12

y=-1

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