-2(z+3)-z=-z-4(2+2)

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Solution for -2(z+3)-z=-z-4(2+2) equation: 



-2(z+3)-z=-z-4(2+2)

We move all terms to the left:

-2(z+3)-z-(-z-4(2+2))=0

We add all the numbers together, and all the variables

-2(z+3)-z-(-z-44)=0

We add all the numbers together, and all the variables

-1z-2(z+3)-(-z-44)=0

We multiply parentheses

-1z-2z-(-z-44)-6=0

We get rid of parentheses

-1z-2z+z+44-6=0

We add all the numbers together, and all the variables

-2z+38=0

We move all terms containing z to the left, all other terms to the right

-2z=-38

z=-38/-2

z=+19

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