7y+5(3-2y)=18

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Solution for 7y+5(3-2y)=18 equation: 



7y+5(3-2y)=18

We move all terms to the left:

7y+5(3-2y)-(18)=0

We add all the numbers together, and all the variables

7y+5(-2y+3)-18=0

We multiply parentheses

7y-10y+15-18=0

We add all the numbers together, and all the variables

-3y-3=0

We move all terms containing y to the left, all other terms to the right

-3y=3

y=3/-3

y=-1

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