-2(z+3)-2=-z-4(z+2)

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Solution for -2(z+3)-2=-z-4(z+2) equation: 



-2(z+3)-2=-z-4(z+2)

We move all terms to the left:

-2(z+3)-2-(-z-4(z+2))=0

We multiply parentheses

-2z-(-z-4(z+2))-6-2=0



We calculate terms in parentheses: -(-z-4(z+2)), so:

-z-4(z+2)

We add all the numbers together, and all the variables

-1z-4(z+2)

We multiply parentheses

-1z-4z-8

We add all the numbers together, and all the variables

-5z-8

Back to the equation:

-(-5z-8)



We add all the numbers together, and all the variables

-2z-(-5z-8)-8=0

We get rid of parentheses

-2z+5z+8-8=0

We add all the numbers together, and all the variables

3z=0

z=0/3

z=0

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