6(2l+3)=150

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Solution for 6(2l+3)=150 equation: 



6(2l+3)=150

We move all terms to the left:

6(2l+3)-(150)=0

We multiply parentheses

12l+18-150=0

We add all the numbers together, and all the variables

12l-132=0

We move all terms containing l to the left, all other terms to the right

12l=132

l=132/12

l=11

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