-2(y-5)-(5y-2)=-3-(4y-2)

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Solution for -2(y-5)-(5y-2)=-3-(4y-2) equation: 



-2(y-5)-(5y-2)=-3-(4y-2)

We move all terms to the left:

-2(y-5)-(5y-2)-(-3-(4y-2))=0

We multiply parentheses

-2y-(5y-2)-(-3-(4y-2))+10=0

We get rid of parentheses

-2y-5y-(-3-(4y-2))+2+10=0



We calculate terms in parentheses: -(-3-(4y-2)), so:

-3-(4y-2)

determiningTheFunctionDomain
-(4y-2)-3

We get rid of parentheses

-4y+2-3

We add all the numbers together, and all the variables

-4y-1

Back to the equation:

-(-4y-1)



We add all the numbers together, and all the variables

-7y-(-4y-1)+12=0

We get rid of parentheses

-7y+4y+1+12=0

We add all the numbers together, and all the variables

-3y+13=0

We move all terms containing y to the left, all other terms to the right

-3y=-13

y=-13/-3

y=4+1/3

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