12(-30+2y)=4y-(-36-9y)

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Solution for 12(-30+2y)=4y-(-36-9y) equation: 



12(-30+2y)=4y-(-36-9y)

We move all terms to the left:

12(-30+2y)-(4y-(-36-9y))=0

We add all the numbers together, and all the variables

12(2y-30)-(4y-(-9y-36))=0

We multiply parentheses

24y-(4y-(-9y-36))-360=0



We calculate terms in parentheses: -(4y-(-9y-36)), so:

4y-(-9y-36)

We get rid of parentheses

4y+9y+36

We add all the numbers together, and all the variables

13y+36

Back to the equation:

-(13y+36)



We get rid of parentheses

24y-13y-36-360=0

We add all the numbers together, and all the variables

11y-396=0

We move all terms containing y to the left, all other terms to the right

11y=396

y=396/11

y=36

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