-2(y-4y)+9=-6(2y-y)+5+11y

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Solution for -2(y-4y)+9=-6(2y-y)+5+11y equation: 



-2(y-4y)+9=-6(2y-y)+5+11y

We move all terms to the left:

-2(y-4y)+9-(-6(2y-y)+5+11y)=0

We add all the numbers together, and all the variables

-2(-3y)-(-6(+y)+5+11y)+9=0

We multiply parentheses

6y-(-6(+y)+5+11y)+9=0



We calculate terms in parentheses: -(-6(+y)+5+11y), so:

-6(+y)+5+11y

determiningTheFunctionDomain
-6(+y)+11y+5

We add all the numbers together, and all the variables

11y-6(+y)+5

We multiply parentheses

11y-6y+5

We add all the numbers together, and all the variables

5y+5

Back to the equation:

-(5y+5)



We get rid of parentheses

6y-5y-5+9=0

We add all the numbers together, and all the variables

y+4=0

We move all terms containing y to the left, all other terms to the right

y=-4

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