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12-2(x+3)=6-2x
We move all terms to the left:
12-2(x+3)-(6-2x)=0
We add all the numbers together, and all the variables
-2(x+3)-(-2x+6)+12=0
We multiply parentheses
-2x-(-2x+6)-6+12=0
We get rid of parentheses
-2x+2x-6-6+12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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