-2(y-3y)+5=-3(5y-y)+8+15

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Solution for -2(y-3y)+5=-3(5y-y)+8+15 equation: 



-2(y-3y)+5=-3(5y-y)+8+15

We move all terms to the left:

-2(y-3y)+5-(-3(5y-y)+8+15)=0

We add all the numbers together, and all the variables

-2(-2y)-(-3(+4y)+8+15)+5=0

We multiply parentheses

4y-(-3(+4y)+8+15)+5=0



We calculate terms in parentheses: -(-3(+4y)+8+15), so:

-3(+4y)+8+15

We add all the numbers together, and all the variables

-3(+4y)+23

We multiply parentheses

-12y+23

Back to the equation:

-(-12y+23)



We get rid of parentheses

4y+12y-23+5=0

We add all the numbers together, and all the variables

16y-18=0

We move all terms containing y to the left, all other terms to the right

16y=18

y=18/16

y=1+1/8

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