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2+13x-7x^2=0
a = -7; b = 13; c = +2;
Δ = b2-4ac
Δ = 132-4·(-7)·2
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-15}{2*-7}=\frac{-28}{-14} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+15}{2*-7}=\frac{2}{-14} =-1/7 $
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