-2(x-4)+6x=4(x-3)

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Solution for -2(x-4)+6x=4(x-3) equation: 



-2(x-4)+6x=4(x-3)

We move all terms to the left:

-2(x-4)+6x-(4(x-3))=0

We add all the numbers together, and all the variables

6x-2(x-4)-(4(x-3))=0

We multiply parentheses

6x-2x-(4(x-3))+8=0



We calculate terms in parentheses: -(4(x-3)), so:

4(x-3)

We multiply parentheses

4x-12

Back to the equation:

-(4x-12)



We add all the numbers together, and all the variables

4x-(4x-12)+8=0

We get rid of parentheses

4x-4x+12+8=0

We add all the numbers together, and all the variables

20!=0

There is no solution for this equation

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