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-6(x+9)(x-5)=0
We multiply parentheses ..
-6(+x^2-5x+9x-45)=0
We multiply parentheses
-6x^2+30x-54x+270=0
We add all the numbers together, and all the variables
-6x^2-24x+270=0
a = -6; b = -24; c = +270;
Δ = b2-4ac
Δ = -242-4·(-6)·270
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7056}=84$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-84}{2*-6}=\frac{-60}{-12} =+5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+84}{2*-6}=\frac{108}{-12} =-9 $
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