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-2(x+2)=2/5(5+10x)
We move all terms to the left:
-2(x+2)-(2/5(5+10x))=0
Domain of the equation: 5(5+10x))!=0We add all the numbers together, and all the variables
x∈R
-2(x+2)-(2/5(10x+5))=0
We multiply parentheses
-2x-(2/5(10x+5))-4=0
We multiply all the terms by the denominator
-2x*5(10x+5))-(2-4*5(10x+5))=0
Wy multiply elements
-10x^2(1-20x(1=0
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