(4x+53)=(6x-28)

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Solution for (4x+53)=(6x-28) equation:



(4x+53)=(6x-28)
We move all terms to the left:
(4x+53)-((6x-28))=0
We get rid of parentheses
4x-((6x-28))+53=0
We calculate terms in parentheses: -((6x-28)), so:
(6x-28)
We get rid of parentheses
6x-28
Back to the equation:
-(6x-28)
We get rid of parentheses
4x-6x+28+53=0
We add all the numbers together, and all the variables
-2x+81=0
We move all terms containing x to the left, all other terms to the right
-2x=-81
x=-81/-2
x=40+1/2

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