-2(v2)=-3-2v

Solution for -2(v2)=-3-2v equation:

-2(v2)=-3-2v

We move all terms to the left:

-2(v2)-(-3-2v)=0

We add all the numbers together, and all the variables

-2v2-(-2v-3)=0

We add all the numbers together, and all the variables

-2v^2-(-2v-3)=0

We get rid of parentheses

-2v^2+2v+3=0

a = -2; b = 2; c = +3;
Δ = b2-4ac
Δ = 22-4·(-2)·3
Δ = 28
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{28}=\sqrt{4*7}=\sqrt{4}*\sqrt{7}=2\sqrt{7}$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{7}}{2*-2}=\frac{-2-2\sqrt{7}}{-4}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{7}}{2*-2}=\frac{-2+2\sqrt{7}}{-4}
$