-4(u-3)=3u+19

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Solution for -4(u-3)=3u+19 equation: 



-4(u-3)=3u+19

We move all terms to the left:

-4(u-3)-(3u+19)=0

We multiply parentheses

-4u-(3u+19)+12=0

We get rid of parentheses

-4u-3u-19+12=0

We add all the numbers together, and all the variables

-7u-7=0

We move all terms containing u to the left, all other terms to the right

-7u=7

u=7/-7

u=-1

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