-2(v+4)=2v-2+2(3v+4)

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Solution for -2(v+4)=2v-2+2(3v+4) equation: 



-2(v+4)=2v-2+2(3v+4)

We move all terms to the left:

-2(v+4)-(2v-2+2(3v+4))=0

We multiply parentheses

-2v-(2v-2+2(3v+4))-8=0



We calculate terms in parentheses: -(2v-2+2(3v+4)), so:

2v-2+2(3v+4)

determiningTheFunctionDomain
2v+2(3v+4)-2

We multiply parentheses

2v+6v+8-2

We add all the numbers together, and all the variables

8v+6

Back to the equation:

-(8v+6)



We get rid of parentheses

-2v-8v-6-8=0

We add all the numbers together, and all the variables

-10v-14=0

We move all terms containing v to the left, all other terms to the right

-10v=14

v=14/-10

v=-1+2/5

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