1/5(10x-20)=1/2(8x-4)

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Solution for 1/5(10x-20)=1/2(8x-4) equation: 



1/5(10x-20)=1/2(8x-4)

We move all terms to the left:

1/5(10x-20)-(1/2(8x-4))=0



Domain of the equation: 5(10x-20)!=0

x∈R





Domain of the equation: 2(8x-4))!=0

x∈R



We calculate fractions


(2x8/(5(10x-20)*2(8x-4)))+(-5x1/(5(10x-20)*2(8x-4)))=0



We calculate terms in parentheses: +(2x8/(5(10x-20)*2(8x-4))), so:

2x8/(5(10x-20)*2(8x-4))

We multiply all the terms by the denominator


2x8

We add all the numbers together, and all the variables

2x^8

We do not support expression: x^8

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