-2(v+1)=2v-4+3(2v+2)

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Solution for -2(v+1)=2v-4+3(2v+2) equation: 



-2(v+1)=2v-4+3(2v+2)

We move all terms to the left:

-2(v+1)-(2v-4+3(2v+2))=0

We multiply parentheses

-2v-(2v-4+3(2v+2))-2=0



We calculate terms in parentheses: -(2v-4+3(2v+2)), so:

2v-4+3(2v+2)

determiningTheFunctionDomain
2v+3(2v+2)-4

We multiply parentheses

2v+6v+6-4

We add all the numbers together, and all the variables

8v+2

Back to the equation:

-(8v+2)



We get rid of parentheses

-2v-8v-2-2=0

We add all the numbers together, and all the variables

-10v-4=0

We move all terms containing v to the left, all other terms to the right

-10v=4

v=4/-10

v=-2/5

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