-2(u+1)=3u-8+3(3u+8)

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Solution for -2(u+1)=3u-8+3(3u+8) equation:



-2(u+1)=3u-8+3(3u+8)
We move all terms to the left:
-2(u+1)-(3u-8+3(3u+8))=0
We multiply parentheses
-2u-(3u-8+3(3u+8))-2=0
We calculate terms in parentheses: -(3u-8+3(3u+8)), so:
3u-8+3(3u+8)
determiningTheFunctionDomain 3u+3(3u+8)-8
We multiply parentheses
3u+9u+24-8
We add all the numbers together, and all the variables
12u+16
Back to the equation:
-(12u+16)
We get rid of parentheses
-2u-12u-16-2=0
We add all the numbers together, and all the variables
-14u-18=0
We move all terms containing u to the left, all other terms to the right
-14u=18
u=18/-14
u=-1+2/7

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