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6(2x+3)(5x+3)=0
We multiply parentheses ..
6(+10x^2+6x+15x+9)=0
We multiply parentheses
60x^2+36x+90x+54=0
We add all the numbers together, and all the variables
60x^2+126x+54=0
a = 60; b = 126; c = +54;
Δ = b2-4ac
Δ = 1262-4·60·54
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2916}=54$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(126)-54}{2*60}=\frac{-180}{120} =-1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(126)+54}{2*60}=\frac{-72}{120} =-3/5 $
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