-2(m-1)+3m=-5+4(2+m)

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Solution for -2(m-1)+3m=-5+4(2+m) equation: 



-2(m-1)+3m=-5+4(2+m)

We move all terms to the left:

-2(m-1)+3m-(-5+4(2+m))=0

We add all the numbers together, and all the variables

-2(m-1)+3m-(-5+4(m+2))=0

We add all the numbers together, and all the variables

3m-2(m-1)-(-5+4(m+2))=0

We multiply parentheses

3m-2m-(-5+4(m+2))+2=0



We calculate terms in parentheses: -(-5+4(m+2)), so:

-5+4(m+2)

determiningTheFunctionDomain
4(m+2)-5

We multiply parentheses

4m+8-5

We add all the numbers together, and all the variables

4m+3

Back to the equation:

-(4m+3)



We add all the numbers together, and all the variables

m-(4m+3)+2=0

We get rid of parentheses

m-4m-3+2=0

We add all the numbers together, and all the variables

-3m-1=0

We move all terms containing m to the left, all other terms to the right

-3m=1

m=1/-3

m=-1/3

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