-(x-3)+4(5-x)=12(x-1)-4x

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Solution for -(x-3)+4(5-x)=12(x-1)-4x equation: 



-(x-3)+4(5-x)=12(x-1)-4x

We move all terms to the left:

-(x-3)+4(5-x)-(12(x-1)-4x)=0

We add all the numbers together, and all the variables

-(x-3)+4(-1x+5)-(12(x-1)-4x)=0

We multiply parentheses

-(x-3)-4x-(12(x-1)-4x)+20=0

We get rid of parentheses

-x-4x-(12(x-1)-4x)+3+20=0



We calculate terms in parentheses: -(12(x-1)-4x), so:

12(x-1)-4x

We add all the numbers together, and all the variables

-4x+12(x-1)

We multiply parentheses

-4x+12x-12

We add all the numbers together, and all the variables

8x-12

Back to the equation:

-(8x-12)



We add all the numbers together, and all the variables

-5x-(8x-12)+23=0

We get rid of parentheses

-5x-8x+12+23=0

We add all the numbers together, and all the variables

-13x+35=0

We move all terms containing x to the left, all other terms to the right

-13x=-35

x=-35/-13

x=2+9/13

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