-2(k-10)=5-(k-3)

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Solution for -2(k-10)=5-(k-3) equation: 



-2(k-10)=5-(k-3)

We move all terms to the left:

-2(k-10)-(5-(k-3))=0

We multiply parentheses

-2k-(5-(k-3))+20=0



We calculate terms in parentheses: -(5-(k-3)), so:

5-(k-3)

determiningTheFunctionDomain
-(k-3)+5

We get rid of parentheses

-k+3+5

We add all the numbers together, and all the variables

-1k+8

Back to the equation:

-(-1k+8)



We get rid of parentheses

-2k+1k-8+20=0

We add all the numbers together, and all the variables

-1k+12=0

We move all terms containing k to the left, all other terms to the right

-k=-12

k=-12/-1

k=+12

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