1/4t+4=3/4(t+80

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Solution for 1/4t+4=3/4(t+80 equation: 



1/4t+4=3/4(t+80

We move all terms to the left:

1/4t+4-(3/4(t+80)=0



Domain of the equation: 4t!=0

t!=0/4

t!=0

t∈R





Domain of the equation: 4(t+80)+4!=0

We move all terms containing t to the left, all other terms to the right

4(t+80)!=-4

t∈R



We calculate fractions


(4t(t+4)/(16t^2(t+4)+(-(3*4t)/(16t^2(t+4)=0



We calculate terms in parentheses: +(4t(t+4)/(16t^2(t+4)+(-(3*4t)/(16t^2(t+4), so:

4t(t+4)/(16t^2(t+4)+(-(3*4t)/(16t^2(t+4

We can not solve this equation

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