-2(k+4)=3(k-2)

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Solution for -2(k+4)=3(k-2) equation: 



-2(k+4)=3(k-2)

We move all terms to the left:

-2(k+4)-(3(k-2))=0

We multiply parentheses

-2k-(3(k-2))-8=0



We calculate terms in parentheses: -(3(k-2)), so:

3(k-2)

We multiply parentheses

3k-6

Back to the equation:

-(3k-6)



We get rid of parentheses

-2k-3k+6-8=0

We add all the numbers together, and all the variables

-5k-2=0

We move all terms containing k to the left, all other terms to the right

-5k=2

k=2/-5

k=-2/5

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