-2(b-3+4b)=-4b+42

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Solution for -2(b-3+4b)=-4b+42 equation: 



-2(b-3+4b)=-4b+42

We move all terms to the left:

-2(b-3+4b)-(-4b+42)=0

We add all the numbers together, and all the variables

-2(5b-3)-(-4b+42)=0

We multiply parentheses

-10b-(-4b+42)+6=0

We get rid of parentheses

-10b+4b-42+6=0

We add all the numbers together, and all the variables

-6b-36=0

We move all terms containing b to the left, all other terms to the right

-6b=36

b=36/-6

b=-6

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