(4n+-20)=(2n+20)+n

Solution for (4n+-20)=(2n+20)+n equation:

(4n+-20)=(2n+20)+n

We move all terms to the left:

(4n+-20)-((2n+20)+n)=0

We add all the numbers together, and all the variables

(4n-20)-((2n+20)+n)=0

We get rid of parentheses

4n-((2n+20)+n)-20=0


We calculate terms in parentheses: -((2n+20)+n), so:

(2n+20)+n

We add all the numbers together, and all the variables

n+(2n+20)

We get rid of parentheses

n+2n+20

We add all the numbers together, and all the variables

3n+20

Back to the equation:

-(3n+20)


We get rid of parentheses

4n-3n-20-20=0

We add all the numbers together, and all the variables

n-40=0

We move all terms containing n to the left, all other terms to the right

n=40