(4n+20)=(2n+20)+n

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Solution for (4n+20)=(2n+20)+n equation: 



(4n+20)=(2n+20)+n

We move all terms to the left:

(4n+20)-((2n+20)+n)=0

We get rid of parentheses

4n-((2n+20)+n)+20=0



We calculate terms in parentheses: -((2n+20)+n), so:

(2n+20)+n

We add all the numbers together, and all the variables

n+(2n+20)

We get rid of parentheses

n+2n+20

We add all the numbers together, and all the variables

3n+20

Back to the equation:

-(3n+20)



We get rid of parentheses

4n-3n-20+20=0

We add all the numbers together, and all the variables

n=0

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