-2(a+3)4a=18

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Solution for -2(a+3)4a=18 equation:



-2(a+3)4a=18
We move all terms to the left:
-2(a+3)4a-(18)=0
We multiply parentheses
-8a^2-24a-18=0
a = -8; b = -24; c = -18;
Δ = b2-4ac
Δ = -242-4·(-8)·(-18)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{24}{-16}=-1+1/2$

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