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8x-2(x1)=2(3x-1)
We move all terms to the left:
8x-2(x1)-(2(3x-1))=0
We add all the numbers together, and all the variables
6x-(2(3x-1))=0
We calculate terms in parentheses: -(2(3x-1)), so:We get rid of parentheses
2(3x-1)
We multiply parentheses
6x-2
Back to the equation:
-(6x-2)
6x-6x+2=0
We add all the numbers together, and all the variables
2!=0
There is no solution for this equation
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