-2(8-11k)=4(k-4)+7k

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Solution for -2(8-11k)=4(k-4)+7k equation:



-2(8-11k)=4(k-4)+7k
We move all terms to the left:
-2(8-11k)-(4(k-4)+7k)=0
We add all the numbers together, and all the variables
-2(-11k+8)-(4(k-4)+7k)=0
We multiply parentheses
22k-(4(k-4)+7k)-16=0
We calculate terms in parentheses: -(4(k-4)+7k), so:
4(k-4)+7k
We add all the numbers together, and all the variables
7k+4(k-4)
We multiply parentheses
7k+4k-16
We add all the numbers together, and all the variables
11k-16
Back to the equation:
-(11k-16)
We get rid of parentheses
22k-11k+16-16=0
We add all the numbers together, and all the variables
11k=0
k=0/11
k=0

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