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3x=5/6x+13
We move all terms to the left:
3x-(5/6x+13)=0
Domain of the equation: 6x+13)!=0We get rid of parentheses
x∈R
3x-5/6x-13=0
We multiply all the terms by the denominator
3x*6x-13*6x-5=0
Wy multiply elements
18x^2-78x-5=0
a = 18; b = -78; c = -5;
Δ = b2-4ac
Δ = -782-4·18·(-5)
Δ = 6444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6444}=\sqrt{36*179}=\sqrt{36}*\sqrt{179}=6\sqrt{179}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-78)-6\sqrt{179}}{2*18}=\frac{78-6\sqrt{179}}{36} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-78)+6\sqrt{179}}{2*18}=\frac{78+6\sqrt{179}}{36} $
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