-2(5z+2)=3(3z+5)

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Solution for -2(5z+2)=3(3z+5) equation: 



-2(5z+2)=3(3z+5)

We move all terms to the left:

-2(5z+2)-(3(3z+5))=0

We multiply parentheses

-10z-(3(3z+5))-4=0



We calculate terms in parentheses: -(3(3z+5)), so:

3(3z+5)

We multiply parentheses

9z+15

Back to the equation:

-(9z+15)



We get rid of parentheses

-10z-9z-15-4=0

We add all the numbers together, and all the variables

-19z-19=0

We move all terms containing z to the left, all other terms to the right

-19z=19

z=19/-19

z=-1

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