-7(v+2)=5v-6+2(3v+3)

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Solution for -7(v+2)=5v-6+2(3v+3) equation: 



-7(v+2)=5v-6+2(3v+3)

We move all terms to the left:

-7(v+2)-(5v-6+2(3v+3))=0

We multiply parentheses

-7v-(5v-6+2(3v+3))-14=0



We calculate terms in parentheses: -(5v-6+2(3v+3)), so:

5v-6+2(3v+3)

determiningTheFunctionDomain
5v+2(3v+3)-6

We multiply parentheses

5v+6v+6-6

We add all the numbers together, and all the variables

11v

Back to the equation:

-(11v)



We add all the numbers together, and all the variables

-18v-14=0

We move all terms containing v to the left, all other terms to the right

-18v=14

v=14/-18

v=-7/9

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