-2(4y-4)+8y=8+6(3y-1)

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Solution for -2(4y-4)+8y=8+6(3y-1) equation: 



-2(4y-4)+8y=8+6(3y-1)

We move all terms to the left:

-2(4y-4)+8y-(8+6(3y-1))=0

We add all the numbers together, and all the variables

8y-2(4y-4)-(8+6(3y-1))=0

We multiply parentheses

8y-8y-(8+6(3y-1))+8=0



We calculate terms in parentheses: -(8+6(3y-1)), so:

8+6(3y-1)

determiningTheFunctionDomain
6(3y-1)+8

We multiply parentheses

18y-6+8

We add all the numbers together, and all the variables

18y+2

Back to the equation:

-(18y+2)



We add all the numbers together, and all the variables

-(18y+2)+8=0

We get rid of parentheses

-18y-2+8=0

We add all the numbers together, and all the variables

-18y+6=0

We move all terms containing y to the left, all other terms to the right

-18y=-6

y=-6/-18

y=1/3

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